Question 1:

Gravitational Potential Energy

The gravitational potential energy (GPE) of an object is calculated using the formula GPE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the vertical height.

• Mass m = 6 kg

• Height h = 3 m

• Acceleration due to gravity (g) ≈ 10 m/s ² GPE = (6 kg) × (10 m/s ²) × (3 m) = 180 J

  This corresponds to answer C.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
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Question 2:

Kinetic Energy at the bottom of the slope

Since the slope is frictionless and air resistance is ignored, the principle of conservation of mechanical energy applies. This means that the gravitational potential energy at the top of the slope is completely converted into kinetic energy at the bottom. KE bottom = GPE top = 180 J

This corresponds to answer C.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 4:

Kinetic Energy (KE)
The kinetic energy is the energy of motion and is calculated using the formula:
KE = ½mv²

Where:

m = mass = 2 kg and v = velocity = 5 m/s

KE = ½mv² = KE = ½.2. 5²
​
KE=25 J

Gravitational Potential Energy (GPE)
The gravitational potential energy is the energy stored by an object due to its position in a gravitational field and is calculated using the formula:
GPE=mgh
Where:

m = mass = 2 kg, g = acceleration due to gravity ≈10 m/s², and h = height = 1.5 m

GPE=(2 kg)(10 m/s²)(1.5 m)
GPE=30 J

The correct answer is C.

The kinetic energy of the brick is 25 J, and its gravitational potential energy is 30 J.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 5:

Electrical Energy Supplied
To find the energy supplied, use the formula for energy, which is power multiplied by time. First, convert the time from minutes to seconds.
5 minutes=5×60 seconds=300 s
Now, calculate the energy (E):
E=P×t
E=50 W×300 s=15000 J
Since the options are in kilojoules (kJ), convert the energy:
15000 J÷1000=15 kJ

This corresponds to answer A.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 6:

Visible Light Output
Efficiency is the ratio of useful power output to the total power input.
Efficiency= Useful Power Output ÷ Total Power Input

​

In this case, the useful power is the visible light output. Rearrange the formula to solve for the useful power output:
Useful Power Output=Efficiency × Total Power Input
Useful Power Output=0.20×50 W=10 W

This corresponds to answer A.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 7:

The elastic potential energy stored in a stretched material is directly proportional to the square of its extension. The formula for elastic potential energy (E) is:
E=½kx²

Where:

k is the spring constant of the material.

x is the extension.

Initially, the energy stored is E= E=½kx².

When the extension is increased to 4x, the new energy (E_new) is:
E_new= ½kx²
E_new= ½k(4x)²
E_new= ½k.16. x²

Since the original energy E=½kx² , we can substitute this into the equation:
E_new=16E

Doubling the extension increases the stored energy by a factor of 4. Therefore, increasing the extension by a factor of 4 increases the stored energy by a factor of 4² =16.

The correct answer is D. 16 E.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 8:

The energy stored in a stretched rope or spring is equal to the work done to stretch it. On a force-extension graph, the work done is represented by the area under the curve.

For an ideal spring that obeys Hooke's Law (where the graph is a straight line), the area is a triangle, and the stored energy is given by the formula E=½Fx or E =½kx².

For a material like a climbing rope that does not have a linear force-extension relationship, the graph is a curve. In this case, the stored energy can only be found by calculating the area under that specific curved line.

The gradient of the line represents the stiffness of the material at a given point, not the energy stored.

The correct answer is A. The area under the line.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 9:

Work Done
Work done is defined as the component of the force in the direction of motion multiplied by the distance moved.

The force acting in the horizontal direction (the direction of motion) is the horizontal component of the applied force. This is calculated as:

F_x =Fcosθ= 800cosθ.

The distance moved is d=10 m.

The work done (W) is therefore:
W=F x d =(800cosθ)×10=8000 cosθ

This corresponds to answer B.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.

Question 10:

Power Required
Power is the rate at which work is done. It can be calculated as the force in the direction of motion multiplied by the velocity.

The force in the direction of motion is the horizontal component calculated in the previous step:
F_x =Fcosθ= 800 cosθ.

The velocity is v=2 m/s.

The power (P) is therefore:
P=F_x × v=(800cosθ)×2=1600 cosθ 

This corresponds to answer C.

*These A.I. responses have been individually checked to ensure they match the accepted answer, but explanations may still be incorrect. Responses may give guidance but the A.I. might not be able to answer the question! This is particularly the case for questions based on diagrams, which the A.I. typically cannot interpret.
Grade Gorilla uses Gemini, Deepseek and a range of other A.I. chatbots to generate the saved responses. Some answers have had human intervention for clarity or where the A.I. has not been able to answer the question.